Demonstrate The Pythagorean Theorem By Folding A Ci 6TK


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1 - Demonstrate The Pythagorean Theorem By Folding A Ci 6TK
Demonstrate The Pythagorean Theorem By Folding A Ci 6TK
Autor: Bradford Hansen-Smith
Category: Education
Published: 2011-09-23

Demonstrate The Pythagorean Theorem By Folding A Ci 6TK. From http:/ / www.wholemovement.com the Pythagorean Theorem revealed in the proportional relationships of right triangles within two folds of the circle (using a paper plate). A low-cost hands-on classroom activity for teaching math and geometry.

How to make an Origami Demonstrate The Pythagorean Theorem By Folding A Ci 6TK Model was made on 2011-09-23 by Bradford Hansen-Smith. In this section you will find a Video Tutorial published on YouTube, about how to fold an origami model or the step by step instructions to make it. I hope you found the instructions clear and I hope you enjoy folding It.



Christmas Video Gallery > Sacred 1 > Demonstrate The Pythagorean Theorem By Folding A Ci 6TK

Ralph schraven [19-Apr-2015]
Sadly this video does not show the pythagorean theorem at all; let alone by folding a circle. the circle draws unnecessary attention in that it is merely used to draw straight lines: any irrelevant context is usually left out, thus lines that are independent of their environment are usually drawn on a background that is only rectangular because of shipping purposes. note that when one would want to construct a 90 degree angle, using circles is very effective, but usually this is learned to children separate from the pythagorean theorem. now for the explanation of the sides of the triangle and its area, i think you imagine the separate areas of the rhomboid to represent a^2, b^2 and c^2 correspondingly, but this is not true: all those areas are equal. you should have shown us that these triangles, which all have area a*b/2, equate to a^2 + b^2, and also equate to c^2, thus completing the proof of the pythagorean theorem. instead, from time to time there were surprising conclusions based off of ab/2 = ab/2 = ab/2, that apparently a^2 + b^2 = c^2. also note that expanding the triangular grid simply creates more of these identical triangles that thus also have identical areas, and identifying different kinds of identical triangles is by definition of identity impossible. there's no such thing as right-handed and left-handed triangles, unless they form vector quantities, which would make the 'sides' not actually sides but vectors. all these irrelevant things, such as orientation of triangles, folding circles to create lines, expanding a grid, names of shapes (rhomboid), are distracting and confusing for those who wish to see a demonstration of the pythagorean theorem.?
Angetothe lol [18-Apr-2015]
This is nonsense.?
Volodya! v anarhist [18-Apr-2015]
You did in fact show rather well how a^2 + b^2 -> c^2, but then you've turnt the circle over drew something, showed the exact same thing almost and then all of the sudden said, 'so there we have it', and you didn't have it yet. maybe there was something in your head that was very clear to you, but if it was, then you were using pythogarean theorem itself to make it clear. you can't do that.?
Dinesh reddy [18-Apr-2015]
Ube.com/feeds/api/videos/6tkyekxi4gk/comments/z13ddnloot3bjzjgr04cejbwszbuvnbjgkk0k2015-03-04t02:41:38.000z2015-03-04t02:41:38.000zdinesh reddyhttp://gdata.youtube.com/feeds/api/users/j6rpztzmvcao-jtraptowqucj6rpztzmvcao-jtraptowq11771938961585729899806tkyekxi4gk
Moose man [18-Apr-2015]
Mixing vector notation and lengths is misleading. i love circles but this is an exercise in misdirection rather than a proof.?
Harisankar aji [17-Apr-2015]
He dosent have idea about the theorem?
Frédéric yargui [17-Apr-2015]
In a first approch i would say that you'd better upload this video on april fool's day.you may hurt people's logic with all those 'non sequitur's (the only logical thing that is answered in the comments zone is the sound of the marker.) yet, i encourage everyone here to take a look at your website, you've done terrific creations with your 'vision'. ?
Pietjepukful [17-Apr-2015]
Don't bogard that joint, i need a hit to follow ?
Miguel ser [16-Apr-2015]
Delirante, no tiene ni pies ni cabeza. ?
Georg lucas scirovicza [16-Apr-2015]
John lokiju [16-Apr-2015]
Pure delirium. this not a demonstration at all. it is a long litany of nonsense.?
Animimm [16-Apr-2015]
Alzheimer's effect?
Abhinav vats [15-Apr-2015]
Rck [15-Apr-2015]
Omg! i thought i was deplorably senseless because i was confused. until i read other comments. ?
Kshitij shekhar [15-Apr-2015]
Nice video?
Lauren case [15-Apr-2015]
Thankyou! this helped :)?
Teacher emily [14-Apr-2015]
My 8th graders are having difficulty understanding pt. i was hoping a hands on activity would help them. i think as a linear thinker mathematician, you have made assumptions about base knowledge and skipped steps/explanations that are clear to you. i'm a global thinker and i don't see a whole picture here, therefore don't understand. i doubt my students will either. too bad.?
Mario g. cardiel [14-Apr-2015]
I guess this is a joke...?
Ciokas [14-Apr-2015]
The idea of using circles, folding them and looking for patterns is very nice and very thought provoking actually, but the maths you do with the circles is wrong. you could use such methods to prove that a^3 + b^3 = c^3 given 3 right triangles, which we know is not right, hence your methods are not correct.?
Sindhu [13-Apr-2015]
I like dis n its v.tough?
Janell evans [13-Apr-2015]
Your thinking process is difficult to follow. i understand that in the first part of the explanation you are showing how area 1 and area 2 combine to make area 3, which demonstrates what you are going to do with the pythagorean theorem. but when you begin your explanation of the pythagorean theorem, i do not understand how the areas relate to a^2 + b^2 = c^2 equation. also, when does c = square root of 2 come from? this is very unique and i'd really like to understand your explanation!
Sukant mallik [13-Apr-2015]
thanks but your marker disturbs you
Bradford hansen-smith [13-Apr-2015]
Touching any 2 points on circumference is a right angle function forming a kite, rhomboid as shown, 4 rts. fold opposite points to get a square, 8 rts, 2 diagonals, 1 diameter is square root of 2. one diameter root of circle. fold 3 diameters a hexagon, 7 points show 36 30-60-90 triangles 3 interrelated sizes in hexagon star. the circle is context; right angle fundamental to all circle does 2-d '3-d. we are confined to 2-d circles to explain formal relationships when circle shows much more.
Jerry lou [12-Apr-2015]
Hate to say, but you are wrong!

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